Originally Posted by nathanlowe

Didnt think of trying two -s

So ( z-3)(z-5) = 0

So z - 3 = 0 or z - 5 = 0

z = 3 or z = 5

The quadratic equation is

Is my answer right or should i have been using that method of finding it when theres a + and a - .

It is a non calc paper tho.